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Methanol

Sean and Matt\

Period 1 Group 11

 

General Info

Chemical Equation:

2CH3OH (l) + 3O2(g) à 2CO2(g) + 4H2O(g) + 736 kJ of heat energy

Liquid methyl alcohol and gaseous oxygen react in a combustion reaction forming gaseous carbon dioxide and gaseous water and 736 kilojoules of heat energy.

Source ---- 1997 Zumdhal Chemistry, Boston, MA, Houghton Miffin Company pg. 120-121


  1. What is this chemical reaction used for?

· Fuel for powering cars

Source --- Source ---- 1997 Zumdhal Chemistry, Boston, MA, Houghton Miffin Company pg. 120-121


 

2. How is the chemical reaction created?

·         The reaction is created when a spark from the starter ignites the fuel (methanol) in the presence of oxygen and creates a combustion reaction in the engine

 Source ---- 1997 Zumdhal Chemistry, Boston, MA, Houghton Miffin Company pg. 120-121, Self Interview


3. How is stoichiometry applied to this chemical reaction?

  • Stoichiometry is applied when we want to find out how much energy methanol is produced by a liter of methanol  in relation to a liter of gasoline.

 Source--- Personal Interview


4. Give a specific stoichiometric problem and solve it for each reactant and product.

 Ratio of energy produced for gasoline and methanol.

Energy produced from the combustion of 1 liter of methanol (CH3OH)

1 liter CH3OH

1000 mL CH3OH

0.791 grams CH3OH

1 mol CH3OH

736 kJ

 = 20,000 kJ

 

 1 L CH3OH

 1 mL CH3OH

 32 grams CH3OH

1 mol CH3OH

 

 

 Energy produced from the combustion of 1 liter of gasoline[isooctane, (CH3)3CCH2CH(CH3)2].

2(CH3)3CCH2CH(CH3)2  + 25 O2 à 16 CO2 + 18 H2O+10,900kJ

 1 liter (CH3)3CCH2CH(CH3)2

 1000 mL (CH3)3CCH2CH(CH3)2

 0.7 grams (CH3)3CCH2CH(CH3)2

 1 mol (CH3)3CCH2CH(CH3)2

10,900 kJ

10,900 kJ

= 70,000 kJ

 

 1 liter (CH3)3CCH2CH(CH3)2

 1 mL (CH3)3CCH2CH(CH3)2

 114 grams (CH3)3CCH2CH(CH3)2

1 mol

(CH3)3CCH2CH(CH3)2

1 mol

 

 The ratio of energy for gasoline to methanol is 70,000 to 20,000; therefore gasoline creates 350 percent more energy per liter.

 

Liters of oxygen required for the combustion of 1 liter of methanol:

1 liter CH3OH

1000 mL CH3OH

0.791grams CH3OH

1 mols CH3OH

3 mols O2

32 grams O2

 1000mL O2

 

 

1 liter CH3OH

1 mL CH3OH

32 grams CH3OH

2 mols CH3OH

1 mol O2

1.429 grams O2

 

1liter CH3OH

= 800 liters O2

1000 mL O2

 

Therefore, the combustion of 1 liter of methanol requires 800 liters of oxygen.

 

Liters of C02 produced by the combustion of  liter of methanol:

1 liter CH3OH

1000 mL CH3OH

0.791grams CH3OH

1 mols CH3OH

2 Mols C02

44 Grams C02

 

1 liter CH3OH

1 mL CH3OH

32 grams CH3OH

2 Mols CH3OH

1Mols C02

 

1000 mL C02

1 liter C02

=500 liters C02

2 grams C02

1000 mL

 

Therefore, 500 liters of CO2 are produced when methanol reacts with oxygen in a combustion reaction.

 

Liters of H20 produced by the combustion of 1 liter of methanol:

1 liter CH3OH

1000 mL CH3OH

0.791grams CH3OH

1 mols

 

1 liter CH3OH

1 mL CH3OH

32 grams CH3OH

 

4 mols H20

18 grams H20

1mL H20

1liter H20

0.9 liters H20

2 mols CH3OH

1 mol H20

1grams H20

1000 mL H20

 

Therefore, 0.9 liters of H20 are produced when methanol reacts with oxygen in a combustion reaction.

 

Source---2002 Chemistry in the Community, United States of America, American Chemical Society pg 211, 2000 Holt Chemistry Visualizing Matter Austin, Texas, Holt Rinehart and Winston pg. 370, 371, 1993 Modern Chemistry, Boca Raton, Florida, Dell Publishing Group page 290 


5. Are any of your reactants normally the excess or limiting reactant? Explain why.

  • Methanol is the limiting reactant and oxygen is the excess reactant because it is found all through our atmosphere, while methanol is limited by the amount in the gas tank.

 

 


 

 

 

6. How much will the main chemical reaction above cost to produce?

Cost for 1 liter of methanol (CH3OH):

1 liter CH3OH

5.25 dollars

10.50 dollars

 

.5 liter CH3OH

 

 Source---2002 Flinn Chemical & Biological Catalog Reference Manual 2002 Batavia, IL, Flinn Science pg. 114


7. Are their any side reactions or dangers from the original chemical reaction that must be compensated for? If yes, how is it done?

  • The reaction is a combustion reaction so if the engine in the car were to malfunction, there could be an explosion.
  • This can be prevented if the mechanic checks the engine to make sure it is safe to run.

8. Bibliography

 

  • 1997 Zumdhal Chemistry, Boston, MA, Houghton Miffin Company  pg. 120-121
  • 2002 Chemistry in the Community, United States of America, American Chemical Society pg 211
  • 2000 Holt Chemistry Visualizing Matter Austin, Texas, Holt Rinehart and Winston pg. 370,371
  • 2002 Flinn Chemical & Biological Catalog Reference Manual 2002 Batavia, IL, Flinn Science pg. 114

 

St. Loius School